What is the solution for x((dy)/(dx))=x^3+16x^3y ?

The solution for x((dy)/(dx))=x^3+16x^3y is y=(e^{(16x^3+c_{1})/3})/(16)-1/16

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x((dy)/(dx))=x^3+16x^3y

x (\frac{d y}{d x}) = x^{3} + 16 x^{3} y

y = \frac{e ^{\frac{16 x ^{3} + c _{1}}{3}}}{16} - \frac{1}{16}

Solution steps

x (\frac{d y}{d x}) = x^{3} + 16 x^{3} y

Solve separable ODE:

y = \frac{e ^{\frac{16 x ^{3} + c _{1}}{3}}}{16} - \frac{1}{16}

y = \frac{e ^{\frac{16 x ^{3} + c _{1}}{3}}}{16} - \frac{1}{16}

\frac{\partial}{\partial x} (3 x^{3} y - \frac{4}{x} + 2 y^{\frac{1}{2}})

\int_{\frac{1}{7}}^{3} 8 x ln (7 x) d x

y = 3 x + 6 cos (x), at (\frac{π}{3})

\frac{s}{s ^{2} + 2 s + 3}

f (x) = \frac{2 x ^{3} - 3 x + 1}{x}

What is the solution for x((dy)/(dx))=x^3+16x^3y ?
The solution for x((dy)/(dx))=x^3+16x^3y is y=(e^{(16x^3+c_{1})/3})/(16)-1/16