What is the derivative of-x^3+3x ?

The derivative of-x^3+3x is -3x^2+3

What is the first derivative of-x^3+3x ?

The first derivative of-x^3+3x is -3x^2+3

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\frac{d}{d x} (- x^{3} + 3 x)

- 3 x^{2} + 3

Solution steps

\frac{d}{d x} (- x^{3} + 3 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d x} (x^{3}) + \frac{d}{d x} (3 x)

\frac{d}{d x} (x^{3}) = 3 x^{2}

\frac{d}{d x} (3 x) = 3

= - 3 x^{2} + 3

\frac{\partial}{\partial x} ((x + y)^{5} + (x - y)^{5})

f (x) = tan^{2} (x), at x = - \frac{π}{4}

f (x) = 13 x e^{x}

y = 3 1 + 8 x

\int \frac{1}{2 π} e^{- \frac{x ^{2}}{2}} d x

What is the derivative of-x^3+3x ?
The derivative of-x^3+3x is -3x^2+3
What is the first derivative of-x^3+3x ?
The first derivative of-x^3+3x is -3x^2+3