What is the derivative of sqrt(9z-8) ?

The derivative of sqrt(9z-8) is 9/(2sqrt(9z-8))

What is the first derivative of sqrt(9z-8) ?

The first derivative of sqrt(9z-8) is 9/(2sqrt(9z-8))

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derivative of

9 z - 8

\frac{9}{2 9 z - 8}

Solution steps

\frac{d}{d z} (9 z - 8)

Apply the chain rule:

\frac{1}{2 9 z - 8} \frac{d}{d z} (9 z - 8)

= \frac{1}{2 9 z - 8} \frac{d}{d z} (9 z - 8)

\frac{d}{d z} (9 z - 8) = 9

= \frac{1}{2 9 z - 8} \cdot 9

Simplify

\frac{1}{2 9 z - 8} \cdot 9 : \frac{9}{2 9 z - 8}

= \frac{9}{2 9 z - 8}

\int x^{4} + 4 x^{2} d x

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\frac{\partial}{\partial x} (8 x e^{5 x y})

n = 0 \sum \infty \frac{n !}{1 1 ^{n}}

y = 2 e^{2 e^{x} + x}

What is the derivative of sqrt(9z-8) ?
The derivative of sqrt(9z-8) is 9/(2sqrt(9z-8))
What is the first derivative of sqrt(9z-8) ?
The first derivative of sqrt(9z-8) is 9/(2sqrt(9z-8))