What is the tangent of x^3-6x^2-34x+40,\at x=6 ?

The tangent of x^3-6x^2-34x+40,\at x=6 is y=2x-176

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tangent of x^3-6x^2-34x+40,\at x=6

tangent of

x^{3} - 6 x^{2} - 34 x + 40, at x = 6

y = 2 x - 176

Solution steps

Find the tangent point:

(6, - 164)

Find the slope of

y = x^{3} - 6 x^{2} - 34 x + 40 : \frac{d y}{d x} = 3 x^{2} - 12 x - 34

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 2

Find the line with slope m=

2

and passing through

(6, - 164) : y = 2 x - 176

y = 2 x - 176

\int - k x d x

\int \frac{1}{x ( x + 1 )} d x

x \to 0 lim (\frac{( x + 5 )}{3 x})

y = (t^{2} + 3) e^{t}

y = 3 + 4 x^{2} - 2 x^{3}

What is the tangent of x^3-6x^2-34x+40,\at x=6 ?
The tangent of x^3-6x^2-34x+40,\at x=6 is y=2x-176