What is the derivative of 1+sin(x) ?

The derivative of 1+sin(x) is cos(x)

What is the first derivative of 1+sin(x) ?

The first derivative of 1+sin(x) is cos(x)

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\frac{d}{d x} (1 + sin (x))

cos (x)

Solution steps

\frac{d}{d x} (1 + sin (x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (1) + \frac{d}{d x} (sin (x))

\frac{d}{d x} (1) = 0

\frac{d}{d x} (sin (x)) = cos (x)

= 0 + cos (x)

Simplify

= cos (x)

f (x) = \frac{72}{x}

\frac{d}{d x} ((x + 3)^{2})

4 x^{2} - 5 x

\int \frac{e ^{2 y}}{e ^{2 y} - 1} d y

y^{4} - 4 y^{2} = x^{4} - 9 x^{2}, (3, 2)

What is the derivative of 1+sin(x) ?
The derivative of 1+sin(x) is cos(x)
What is the first derivative of 1+sin(x) ?
The first derivative of 1+sin(x) is cos(x)