What is the derivative of (8x+7^2) ?

The derivative of (8x+7^2) is 16(8x+7)

What is the first derivative of (8x+7^2) ?

The first derivative of (8x+7^2) is 16(8x+7)

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\frac{d}{d x} ((8 x + 7)^{2})

16 (8 x + 7)

Solution steps

\frac{d}{d x} ((8 x + 7)^{2})

Apply the chain rule:

2 (8 x + 7) \frac{d}{d x} (8 x + 7)

= 2 (8 x + 7) \frac{d}{d x} (8 x + 7)

\frac{d}{d x} (8 x + 7) = 8

= 2 (8 x + 7) \cdot 8

Simplify

= 16 (8 x + 7)

\int \frac{1}{cos ( 3 x )} d x

- 9 x^{\frac{1}{2}} + x^{\frac{3}{2}}

(4, - 8), (8, 5)

\frac{d}{d x} (3 x^{4})

x \to 4 lim (\frac{4 - ∣ x ∣}{4 + x})

What is the derivative of (8x+7^2) ?
The derivative of (8x+7^2) is 16(8x+7)
What is the first derivative of (8x+7^2) ?
The first derivative of (8x+7^2) is 16(8x+7)