What is the integral from-infinity to 0 of e^{2x} ?

The integral from-infinity to 0 of e^{2x} is 1/2

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integral from-infinity to 0 of e^{2x}

\int_{- \infty}^{0} e^{2 x} d x

\frac{1}{2}

Decimal

0.5

Solution steps

\int_{- \infty}^{0} e^{2 x} d x

Compute the indefinite integral:

\int e^{2 x} d x = \frac{1}{2} e^{2 x} + C

Compute the boundaries:

\int_{- \infty}^{0} e^{2 x} d x = \frac{1}{2} - 0

= \frac{1}{2} - 0

Simplify

= \frac{1}{2}

\frac{r}{r ^{2} + 2}

\frac{\partial}{\partial x} (x^{2} + y^{2} - y^{2} x - 8)

\int 2 x - \frac{2}{x} d x

\frac{\partial}{\partial y} (x arctan (\frac{y}{z}))

x \to + (- 3) lim (2 x + 5)

What is the integral from-infinity to 0 of e^{2x} ?
The integral from-infinity to 0 of e^{2x} is 1/2