What is the solution for (x)(dy)/(dx)+y= 1/(y^2) ?

The solution for (x)(dy)/(dx)+y= 1/(y^2) is y=(\sqrt[3]{-c_{1}+x^3})/x

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(x)(dy)/(dx)+y= 1/(y^2)

(x) \frac{d y}{d x} + y = \frac{1}{y ^{2}}

y = \frac{3 - c _{1} + x ^{3}}{x}

Solution steps

(x) \frac{d y}{d x} + y = \frac{1}{y ^{2}}

Solve separable ODE:

y = \frac{3 - c _{1} + x ^{3}}{x}

y = \frac{3 - c _{1} + x ^{3}}{x}

\frac{x ^{2} - 9 x + 20}{( x + 2 ) ( x - 2 )}

\int 20 x^{\frac{3}{2}} d x

\frac{2}{2 s - 1}

\frac{d}{d x} (5^{- \frac{x}{2}})

2 \cdot x

What is the solution for (x)(dy)/(dx)+y= 1/(y^2) ?
The solution for (x)(dy)/(dx)+y= 1/(y^2) is y=(\sqrt[3]{-c_{1}+x^3})/x