What is the integral from 0 to pi/3 of sin(2x) ?

The integral from 0 to pi/3 of sin(2x) is 3/4

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integral from 0 to pi/3 of sin(2x)

\int_{0}^{\frac{π}{3}} sin (2 x) d x

\frac{3}{4}

Decimal

0.75

Solution steps

\int_{0}^{\frac{π}{3}} sin (2 x) d x

Apply u-substitution

: \int_{0}^{\frac{2 π}{3}} sin (u) \frac{1}{2} d u

= \int_{0}^{\frac{2 π}{3}} sin (u) \frac{1}{2} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{2} \cdot \int_{0}^{\frac{2 π}{3}} sin (u) d u

Use the common integral:

\int sin (u) d u = - cos (u)

= \frac{1}{2} [- cos (u)]_{0}^{\frac{2 π}{3}}

Compute the boundaries:

\frac{3}{2}

= \frac{1}{2} \cdot \frac{3}{2}

Simplify

= \frac{3}{4}

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What is the integral from 0 to pi/3 of sin(2x) ?
The integral from 0 to pi/3 of sin(2x) is 3/4