What is the derivative of-x+tan(x) ?

The derivative of-x+tan(x) is tan^2(x)

What is the first derivative of-x+tan(x) ?

The first derivative of-x+tan(x) is tan^2(x)

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derivative of

- x + tan (x)

tan^{2} (x)

Solution steps

\frac{d}{d x} (- x + tan (x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d x}{d x} + \frac{d}{d x} (tan (x))

\frac{d x}{d x} = 1

\frac{d}{d x} (tan (x)) = sec^{2} (x)

= - 1 + sec^{2} (x)

Use the Pythagorean identity:

sec^{2} (x) = tan^{2} (x) + 1

sec^{2} (x) - 1 = tan^{2} (x)

= tan^{2} (x)

cos (\frac{1 - e ^{7 x}}{1 + e ^{7 x}})

\frac{\partial}{\partial x} (z x^{2})

f (x) = \frac{x}{x + 100}, at x = 50

\frac{d}{d x} (\frac{x - 5}{x + 1})

\int tan (x) \cdot sec (x) d x

What is the derivative of-x+tan(x) ?
The derivative of-x+tan(x) is tan^2(x)
What is the first derivative of-x+tan(x) ?
The first derivative of-x+tan(x) is tan^2(x)