What is the tangent of x^4-x^5y^2=-3,(1,2) ?

The tangent of x^4-x^5y^2=-3,(1,2) is y=-4x+6

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tangent of x^4-x^5y^2=-3,(1,2)

tangent of

x^{4} - x^{5} y^{2} = - 3, (1, 2)

y = - 4 x + 6

Solution steps

Find the slope of

x^{4} - x^{5} y^{2} = - 3 : \frac{d y}{d x} = - \frac{- 4 + 5 x y ^{2}}{2 x ^{2} y}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - 4

Find the line with slope m=

- 4

and passing through

(1, 2) : y = - 4 x + 6

y = - 4 x + 6

\frac{d}{d x} (- \frac{21}{x ^{4}})

\int x^{2} \cdot ln (x) d x

\int \frac{1}{y - 1} d y

h \to 0 lim (\frac{1 0 ^{h} - 1}{h})

\frac{8}{( 8 - x ^{4} ) ^{\frac{3}{2}}}

What is the tangent of x^4-x^5y^2=-3,(1,2) ?
The tangent of x^4-x^5y^2=-3,(1,2) is y=-4x+6