What is the derivative of 1/(sqrt(9+x^2)) ?

The derivative of 1/(sqrt(9+x^2)) is -x/((9+x^2)^{3/2)}

What is the first derivative of 1/(sqrt(9+x^2)) ?

The first derivative of 1/(sqrt(9+x^2)) is -x/((9+x^2)^{3/2)}

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\frac{d}{d x} (\frac{1}{9 + x ^{2}})

- \frac{x}{( 9 + x ^{2} ) ^{\frac{3}{2}}}

Solution steps

\frac{d}{d x} (\frac{1}{9 + x ^{2}})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= \frac{d}{d x} ((9 + x^{2})^{- \frac{1}{2}})

Apply the chain rule:

- \frac{1}{2 ( 9 + x ^{2} ) ^{\frac{3}{2}}} \frac{d}{d x} (9 + x^{2})

= - \frac{1}{2 ( 9 + x ^{2} ) ^{\frac{3}{2}}} \frac{d}{d x} (9 + x^{2})

\frac{d}{d x} (9 + x^{2}) = 2 x

= - \frac{1}{2 ( 9 + x ^{2} ) ^{\frac{3}{2}}} \cdot 2 x

Simplify

- \frac{1}{2 ( 9 + x ^{2} ) ^{\frac{3}{2}}} \cdot 2 x : - \frac{x}{( 9 + x ^{2} ) ^{\frac{3}{2}}}

= - \frac{x}{( 9 + x ^{2} ) ^{\frac{3}{2}}}

\frac{d}{d x} (x y e^{x y})

\frac{\partial}{\partial x} (5 y - x^{3} y^{2})

\frac{d}{d x} (5 x^{2} sin (x) - x)

\frac{d}{d x} (cos (7))

x y^{^{'}} + y = - 4 x y^{2}

What is the derivative of 1/(sqrt(9+x^2)) ?
The derivative of 1/(sqrt(9+x^2)) is -x/((9+x^2)^{3/2)}
What is the first derivative of 1/(sqrt(9+x^2)) ?
The first derivative of 1/(sqrt(9+x^2)) is -x/((9+x^2)^{3/2)}