What is the integral from-infinity to 0 of 1/(6-5x) ?

The integral from-infinity to 0 of 1/(6-5x) is diverges

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integral from-infinity to 0 of 1/(6-5x)

\int_{- \infty}^{0} \frac{1}{6 - 5 x} d x

diverges

Solution steps

\int_{- \infty}^{0} \frac{1}{6 - 5 x} d x

Compute the indefinite integral:

\int \frac{1}{6 - 5 x} d x = - \frac{1}{5} ln ∣ 6 - 5 x ∣ + C

Compute the boundaries:

\int_{- \infty}^{0} \frac{1}{6 - 5 x} d x =

diverges

= diverges

24 x (3 x^{2} - 1)^{3}

x^{2} \cdot \frac{d y}{d x} = y - x y

\int (x^{2} y) d y

y^{^{''}} + 4 y = x e^{x}

y^{^{''}} - 0.2 y^{^{'}} + 0.01 y = 0, y (0) = 14, y^{^{'}} (0) = b

What is the integral from-infinity to 0 of 1/(6-5x) ?
The integral from-infinity to 0 of 1/(6-5x) is diverges