What is the d/(dt)(1-cos(t)-sin(t)) ?

The d/(dt)(1-cos(t)-sin(t)) is sin(t)-cos(t)

What is the first d/(dt)(1-cos(t)-sin(t)) ?

The first d/(dt)(1-cos(t)-sin(t)) is sin(t)-cos(t)

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\frac{d}{d t} (1 - cos (t) - sin (t))

sin (t) - cos (t)

Solution steps

\frac{d}{d t} (1 - cos (t) - sin (t))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d t} (1) - \frac{d}{d t} (cos (t)) - \frac{d}{d t} (sin (t))

\frac{d}{d t} (1) = 0

\frac{d}{d t} (cos (t)) = - sin (t)

\frac{d}{d t} (sin (t)) = cos (t)

= 0 - (- sin (t)) - cos (t)

Simplify

= sin (t) - cos (t)

\int_{2}^{10} \frac{1}{x} d x

\int 6 x e^{- x^{2}} d x

\frac{d}{d x} (x e^{(2 x)})

\frac{\partial}{\partial x} (9 x^{2} + y^{2})

n = 1 \sum \infty \frac{n + 5}{5 ^{n}}

What is the d/(dt)(1-cos(t)-sin(t)) ?
The d/(dt)(1-cos(t)-sin(t)) is sin(t)-cos(t)
What is the first d/(dt)(1-cos(t)-sin(t)) ?
The first d/(dt)(1-cos(t)-sin(t)) is sin(t)-cos(t)