What is the derivative of (-11/((x-3)^2)) ?

The derivative of (-11/((x-3)^2)) is (22)/((x-3)^3)

What is the first derivative of (-11/((x-3)^2)) ?

The first derivative of (-11/((x-3)^2)) is (22)/((x-3)^3)

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\frac{d}{d x} (\frac{- 11}{( x - 3 ) ^{2}})

\frac{22}{( x - 3 ) ^{3}}

Solution steps

\frac{d}{d x} (\frac{- 11}{( x - 3 ) ^{2}})

Simplify

\frac{- 11}{( x - 3 ) ^{2}} : - \frac{11}{( x - 3 ) ^{2}}

= \frac{d}{d x} (- \frac{11}{( x - 3 ) ^{2}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - 11 \frac{d}{d x} (\frac{1}{( x - 3 ) ^{2}})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= - 11 \frac{d}{d x} ((x - 3)^{- 2})

Apply the chain rule:

- \frac{2}{( x - 3 ) ^{3}} \frac{d}{d x} (x - 3)

= - \frac{2}{( x - 3 ) ^{3}} \frac{d}{d x} (x - 3)

\frac{d}{d x} (x - 3) = 1

= - 11 (- \frac{2}{( x - 3 ) ^{3}} \cdot 1)

Simplify

- 11 (- \frac{2}{( x - 3 ) ^{3}} \cdot 1) : \frac{22}{( x - 3 ) ^{3}}

= \frac{22}{( x - 3 ) ^{3}}

\frac{d}{d x} (x^{2} \cdot sin (x^{3}))

\frac{d}{d x} (\frac{8 e ^{6 x}}{5 x + 2})

\int \frac{1}{2} + \frac{x ^{4}}{4} + \frac{1}{4 x ^{4}} d x

y^{^{''}} + 4 y^{^{'}} + 4 y = 12 t + 16

\int_{0}^{10} 1 + 16 x^{2} d x

What is the derivative of (-11/((x-3)^2)) ?
The derivative of (-11/((x-3)^2)) is (22)/((x-3)^3)
What is the first derivative of (-11/((x-3)^2)) ?
The first derivative of (-11/((x-3)^2)) is (22)/((x-3)^3)