What is (\partial ^2)/(\partial y^2)(y^4cos(2x)) ?

The answer to (\partial ^2)/(\partial y^2)(y^4cos(2x)) is 12y^2cos(2x)

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(\partial ^2)/(\partial y^2)(y^4cos(2x))

\frac{\partial ^{2}}{\partial y ^{2}} (y^{4} cos (2 x))

12 y^{2} cos (2 x)

Solution steps

\frac{\partial ^{2}}{\partial y ^{2}} (y^{4} cos (2 x))

\frac{\partial}{\partial y} (y^{4} cos (2 x)) = 4 y^{3} cos (2 x)

= \frac{\partial}{\partial y} (4 y^{3} cos (2 x))

\frac{\partial}{\partial y} (4 y^{3} cos (2 x)) = 12 y^{2} cos (2 x)

= 12 y^{2} cos (2 x)

y^{^{'}} = 10 y

\frac{d}{d x} (x - \frac{1}{7} x)

\frac{\partial}{\partial x} ((e^{- x}) sin (yz))

\frac{d}{d x} (y cos (2 x))

f (x) = x^{3} - 3 x + 2

What is (\partial ^2)/(\partial y^2)(y^4cos(2x)) ?
The answer to (\partial ^2)/(\partial y^2)(y^4cos(2x)) is 12y^2cos(2x)