What is the solution for y^{''}+y^'-2y=9e^t-6t ?

The solution for y^{''}+y^'-2y=9e^t-6t is y=c_{1}e^t+c_{2}e^{-2t}+3te^t+3t+3/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^{''}+y^'-2y=9e^t-6t

y^{^{''}} + y^{^{'}} - 2 y = 9 e^{t} - 6 t

y = c_{1} e^{t} + c_{2} e^{- 2 t} + 3 t e^{t} + 3 t + \frac{3}{2}

Solution steps

y^{''} (t) + y^{'} (t) - 2 y = 9 e^{t} - 6 t

Solve linear ODE:

y = c_{1} e^{t} + c_{2} e^{- 2 t} + 3 t e^{t} + 3 t + \frac{3}{2}

y = c_{1} e^{t} + c_{2} e^{- 2 t} + 3 t e^{t} + 3 t + \frac{3}{2}

y^{^{'}} - sin (x) y = 3 sin (x)

\frac{d}{d x} (7^{c o s (x)})

\frac{d}{d x} (x^{2} arctan (4 x))

y^{^{''}} + 8 y^{^{'}} + 15 y = 0, y (0) = 0, y^{^{'}} (0) = 0

(x, y) \to (0, 0) lim (x + y)

What is the solution for y^{''}+y^'-2y=9e^t-6t ?
The solution for y^{''}+y^'-2y=9e^t-6t is y=c_{1}e^t+c_{2}e^{-2t}+3te^t+3t+3/2