What is laplacetransform x-1 ?

The answer to laplacetransform x-1 is 1/(s^2)-1/s

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laplacetransform x-1

laplace transform

x - 1

\frac{1}{s ^{2}} - \frac{1}{s}

Solution steps

L {x - 1}

Use the linearity property of Laplace Transform:

For functions

f (t), g (t)

and constants

a, b : L {a \cdot f (t) + b \cdot g (t)} = a \cdot L {f (t)} + b \cdot L {g (t)}

= L {x} - L {1}

L {x} : \frac{1}{s ^{2}}

L {1} : \frac{1}{s}

= \frac{1}{s ^{2}} - \frac{1}{s}

\int e^{x^{3}} x^{2} d x

\int_{0}^{1} (x^{2} - 4 x + 5) d x

n = 1 \sum \infty 2^{- 3 n}

\frac{d}{d y} (9 x e^{- \frac{1}{y ^{3}}})

\int e^{x^{2} + 3} d x

What is laplacetransform x-1 ?
The answer to laplacetransform x-1 is 1/(s^2)-1/s