What is the tangent of 2x^2+x-1,\at x=-1 ?

The tangent of 2x^2+x-1,\at x=-1 is y=-3x-3

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tangent of 2x^2+x-1,\at x=-1

tangent of

2 x^{2} + x - 1, at x = - 1

y = - 3 x - 3

Solution steps

Find the tangent point:

(- 1, 0)

Find the slope of

y = 2 x^{2} + x - 1 : \frac{d y}{d x} = 4 x + 1

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - 3

Find the line with slope m=

- 3

and passing through

(- 1, 0) : y = - 3 x - 3

y = - 3 x - 3

\int cot^{5} (x) sin^{4} (x) d x

\frac{d y}{d x}, cos (x + y) = sin (x) sin (y)

\frac{d}{d x} (e^{2} x)

Y (x) = x^{2} + 3

\frac{t ^{2} + 7}{( 6 t - 2 ) ^{6}}

What is the tangent of 2x^2+x-1,\at x=-1 ?
The tangent of 2x^2+x-1,\at x=-1 is y=-3x-3