What is the solution for y^'=(15x)/y ?

The solution for y^'=(15x)/y is y=sqrt(15x^2+c_{1)},y=-sqrt(15x^2+c_{1)}

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y^'=(15x)/y

y^{^{'}} = \frac{15 x}{y}

y = 15 x^{2} + c_{1}, y = - 15 x^{2} + c_{1}

Solution steps

y^{'} (x) = \frac{15 x}{y}

Solve separable ODE:

y = 15 x^{2} + c_{1}, y = - 15 x^{2} + c_{1}

y = 15 x^{2} + c_{1}, y = - 15 x^{2} + c_{1}

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\frac{\partial}{\partial x} (arctan (x))

\frac{1}{s ^{2} + s ( \frac{3}{2} ) 2}

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\int \frac{x ^{2}}{x ^{2} + x - 2} d x

What is the solution for y^'=(15x)/y ?
The solution for y^'=(15x)/y is y=sqrt(15x^2+c_{1)},y=-sqrt(15x^2+c_{1)}