What is the integral of 1/(tln(t)) ?

The integral of 1/(tln(t)) is ln|ln(t)|+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of 1/(tln(t))

\int \frac{1}{t ln ( t )} d t

ln ∣ ln (t) ∣ + C

Solution steps

\int \frac{1}{t ln ( t )} d t

Apply u-substitution

: \int \frac{1}{u} d u

= \int \frac{1}{u} d u

Use the common integral:

\int \frac{1}{u} d u = ln (∣ u ∣)

= ln ∣ u ∣

Substitute back

u = ln (t)

= ln ∣ ln (t) ∣

Add a constant to the solution

= ln ∣ ln (t) ∣ + C

y = 5 e^{x} + x, (0, 5)

\int \frac{1}{49 - 64 x ^{2}} d x

\int t^{7} e^{- t^{4}} d t

f (x) = \frac{x + 9}{x}

\frac{d}{d x} (\frac{3 x ^{4} + 3}{sin ( x )})