What is the solution for (dy)/(dx)=(x^2+y^2)/(2xy) ?

The solution for (dy)/(dx)=(x^2+y^2)/(2xy) is y=sqrt(x^2+c_{1)x},y=-sqrt(x^2+c_{1)x}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(dy)/(dx)=(x^2+y^2)/(2xy)

\frac{d y}{d x} = \frac{x ^{2} + y ^{2}}{2 x y}

y = x^{2} + c_{1} x, y = - x^{2} + c_{1} x

Solution steps

\frac{d y}{d x} = \frac{x ^{2} + y ^{2}}{2 x y}

Solve Bernoulli ODE:

y = x^{2} + c_{1} x, y = - x^{2} + c_{1} x

y = x^{2} + c_{1} x, y = - x^{2} + c_{1} x

\frac{d}{d x} (cot (x) - sin (2 x))

y = x, x^{2}, [0, 1]

y = - \frac{8 x}{x ^{2} + 1}, (1, - 4)

x^{2} + 2 x + 11, - 4 x + 2, x = 0

x \to 6 lim (∣ x - 6 ∣)

What is the solution for (dy)/(dx)=(x^2+y^2)/(2xy) ?
The solution for (dy)/(dx)=(x^2+y^2)/(2xy) is y=sqrt(x^2+c_{1)x},y=-sqrt(x^2+c_{1)x}