What is the solution for y^{''}-3y^'+2y=e^t+e^{2t} ?

The solution for y^{''}-3y^'+2y=e^t+e^{2t} is y=c_{1}e^{2t}+c_{2}e^t-e^tt+e^{2t}t

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y^{''}-3y^'+2y=e^t+e^{2t}

y^{^{''}} - 3 y^{^{'}} + 2 y = e^{t} + e^{2 t}

y = c_{1} e^{2 t} + c_{2} e^{t} - e^{t} t + e^{2 t} t

Solution steps

y^{''} (t) - 3 y^{'} (t) + 2 y = e^{t} + e^{2 t}

Solve linear ODE:

y = c_{1} e^{2 t} + c_{2} e^{t} - e^{t} t + e^{2 t} t

y = c_{1} e^{2 t} + c_{2} e^{t} - e^{t} t + e^{2 t} t

y = x, y = 2 x, y = - x + 2

\frac{d}{d x} (72 x^{2})

y^{^{''}} + 3 y^{^{'}} + 2 y = x

f (x) = 5 x^{2} - 8 x, at x = 1

x \to 2 lim (a x + b)

What is the solution for y^{''}-3y^'+2y=e^t+e^{2t} ?
The solution for y^{''}-3y^'+2y=e^t+e^{2t} is y=c_{1}e^{2t}+c_{2}e^t-e^tt+e^{2t}t