What is the integral of e^{-z^2} ?

The integral of e^{-z^2} is (sqrt(pi))/2 \erf(z)+C

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integral of e^{-z^2}

\int e^{- z^{2}} d z

\frac{π}{2} erf (z) + C

Solution steps

\int e^{- z^{2}} d z

Use the nonelementary integral:

\int e^{- z^{2}} d z = \frac{π}{2} erf (z)

= \frac{π}{2} erf (z)

Add a constant to the solution

= \frac{π}{2} erf (z) + C

\int \frac{x}{x ^{2} + 4} d x

x \to 2 lim (- \frac{1}{( x - 2 ) ^{2}})

y = x^{2} - x + 7, at x = 7

x \to 1 lim (\frac{x ^{9} - 1}{x - 1})

\frac{d}{d x} (tan (\frac{1}{2} x))

What is the integral of e^{-z^2} ?
The integral of e^{-z^2} is (sqrt(pi))/2 \erf(z)+C