What is the integral from 0 to 1 of (55)/(4y-1) ?

The integral from 0 to 1 of (55)/(4y-1) is diverges

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integral from 0 to 1 of (55)/(4y-1)

\int_{0}^{1} \frac{55}{4 y - 1} d y

diverges

Solution steps

\int_{0}^{1} \frac{55}{4 y - 1} d y

Find undefined (singularity) points:

y = \frac{1}{4}

If exist

b, a < b < c, f (b) =

undefined

, \int_{a}^{c} f (x) d x = \int_{a}^{b} f (x) d x + \int_{b}^{c} f (x) d x

= \int_{0}^{\frac{1}{4}} \frac{55}{4 y - 1} d y + \int_{\frac{1}{4}}^{1} \frac{55}{4 y - 1} d y

\int_{0}^{\frac{1}{4}} \frac{55}{4 y - 1} d y =

diverges

If part of the expression diverges, then entire expression diverges

= diverges

y = lo g_{3} (6 x)

\frac{\partial}{\partial z} (y^{x z} + 2 (yz)^{x})

\int 5 e^{- 3 x} (4 - e^{- 3 x})^{5} d x

\frac{d}{d x} ((4 x^{3} + 5) (x^{4} - 2 x))

x \to 3 lim (\frac{∣ x ∣}{x})

What is the integral from 0 to 1 of (55)/(4y-1) ?
The integral from 0 to 1 of (55)/(4y-1) is diverges