What is the derivative of (x+2)^2+(10-3x)^2 ?

The derivative of (x+2)^2+(10-3x)^2 is 20x-56

What is the first derivative of (x+2)^2+(10-3x)^2 ?

The first derivative of (x+2)^2+(10-3x)^2 is 20x-56

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derivative of

(x + 2)^{2} + (10 - 3 x)^{2}

20 x - 56

Solution steps

\frac{d}{d x} ((x + 2)^{2} + (10 - 3 x)^{2})

Simplify

(x + 2)^{2} + (10 - 3 x)^{2} : 10 x^{2} - 56 x + 104

= \frac{d}{d x} (10 x^{2} - 56 x + 104)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (10 x^{2}) - \frac{d}{d x} (56 x) + \frac{d}{d x} (104)

\frac{d}{d x} (10 x^{2}) = 20 x

\frac{d}{d x} (56 x) = 56

\frac{d}{d x} (104) = 0

= 20 x - 56 + 0

Simplify

= 20 x - 56

x \to - 1 - lim (\frac{x ^{2}}{x + 1})

(1, 0), (0, 1)

\frac{d}{d x} (\frac{2 x - 5}{x})

\int x^{2} - 6 x - 27 d x

4 x \frac{d y}{d x} = x^{2} - 9

What is the derivative of (x+2)^2+(10-3x)^2 ?
The derivative of (x+2)^2+(10-3x)^2 is 20x-56
What is the first derivative of (x+2)^2+(10-3x)^2 ?
The first derivative of (x+2)^2+(10-3x)^2 is 20x-56