What is the derivative of f(x)=26x+ln(26x) ?

The derivative of f(x)=26x+ln(26x) is 26+1/x

What is the first derivative of f(x)=26x+ln(26x) ?

The first derivative of f(x)=26x+ln(26x) is 26+1/x

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derivative of

f (x) = 26 x + ln (26 x)

26 + \frac{1}{x}

Solution steps

\frac{d}{d x} (26 x + ln (26 x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (26 x) + \frac{d}{d x} (ln (26 x))

\frac{d}{d x} (26 x) = 26

\frac{d}{d x} (ln (26 x)) = \frac{1}{x}

= 26 + \frac{1}{x}

\frac{d}{d x} (500 (1 + \frac{x}{1200})^{120})

f (x) = \frac{3 x ^{2}}{2}

x \to 0 lim (x n (x))

\int x^{2} e^{- \frac{x}{a}} d x

\int (cos (y) cos (z)) d y

What is the derivative of f(x)=26x+ln(26x) ?
The derivative of f(x)=26x+ln(26x) is 26+1/x
What is the first derivative of f(x)=26x+ln(26x) ?
The first derivative of f(x)=26x+ln(26x) is 26+1/x