What is the first derivative of b^2 ?

The first derivative of b^2 is 0

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derivative of b^2

derivative of

b^{2}

0

Solution steps

\frac{d}{d y} (b^{2})

Derivative of a constant:

\frac{d}{d x} (a) = 0

= 0

\frac{1}{x ^{2} + 1}

x \to 0 - lim (arctan (\frac{1}{x}) + π)

\frac{d}{d x} (\frac{5}{4 x})

\frac{\partial}{\partial x} (x^{2} + 2 y^{3})

\frac{d y}{d x} = \frac{( y ^{2} + 2 x x ^{2} + y ^{2} )}{x y}