What is (\partial)/(\partial y)(sin(x)*cos(y)) ?

The answer to (\partial)/(\partial y)(sin(x)*cos(y)) is -sin(x)sin(y)

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(\partial)/(\partial y)(sin(x)*cos(y))

\frac{\partial}{\partial y} (sin (x) \cdot cos (y))

- sin (x) sin (y)

Solution steps

\frac{\partial}{\partial y} (sin (x) cos (y))

Treat

x

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= sin (x) \frac{\partial}{\partial y} (cos (y))

Apply the common derivative:

\frac{\partial}{\partial y} (cos (y)) = - sin (y)

= sin (x) (- sin (y))

Simplify

= - sin (x) sin (y)

\frac{3 x}{x - 6}

f (x) = x^{2} e^{x} - 2 x e^{x} + 9 e^{x}

n = 8 \sum \infty \frac{1}{n ( n - 1 )}

\int_{0}^{1} (x^{2} - 4 x + 7) d x

\frac{d}{d x} (- 3 sin (x))

What is (\partial)/(\partial y)(sin(x)*cos(y)) ?
The answer to (\partial)/(\partial y)(sin(x)*cos(y)) is -sin(x)sin(y)