What is the solution for (dr)/(dθ)+rtan(θ)=tan(θ) ?

The solution for (dr)/(dθ)+rtan(θ)=tan(θ) is r(θ)=c_{1}cos(θ)+1

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(dr)/(dθ)+rtan(θ)=tan(θ)

\frac{d r}{d θ} + r tan (θ) = tan (θ)

r (θ) = c_{1} cos (θ) + 1

Solution steps

\frac{d r}{d θ} + r tan (θ) = tan (θ)

Solve separable ODE:

r (θ) = c_{1} cos (θ) + 1

r (θ) = c_{1} cos (θ) + 1

\frac{d}{d x} (\frac{sin ( x ^{2} )}{x ^{3}})

2 (sin (t) y^{^{'}} + cos (t) y) = cos (t) sin^{3} (t)

f (x) = e^{x^{4}}

f (x) = 3 + 5 sin (x)

\int (3 1 + ln (x)) (x^{- 1}) d x

What is the solution for (dr)/(dθ)+rtan(θ)=tan(θ) ?
The solution for (dr)/(dθ)+rtan(θ)=tan(θ) is r(θ)=c_{1}cos(θ)+1