What is the derivative of 2x-1/x ?

The derivative of 2x-1/x is 2+1/(x^2)

What is the first derivative of 2x-1/x ?

The first derivative of 2x-1/x is 2+1/(x^2)

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derivative of

2 x - \frac{1}{x}

2 + \frac{1}{x ^{2}}

Solution steps

\frac{d}{d x} (2 x - \frac{1}{x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x) - \frac{d}{d x} (\frac{1}{x})

\frac{d}{d x} (2 x) = 2

\frac{d}{d x} (\frac{1}{x}) = - \frac{1}{x ^{2}}

= 2 - (- \frac{1}{x ^{2}})

Simplify

= 2 + \frac{1}{x ^{2}}

\frac{d y}{d t} = y^{2} - 2 y - 2

\frac{\partial}{\partial x} (y^{4} cos (6 x))

\int \frac{x ^{2}}{x ^{2} + x + 2} d x

\int \frac{e ^{x}}{4 - 9 e ^{2 x}} d x

\frac{\partial}{\partial x} (5 - x^{4} + 2 x^{2} - y^{2})

What is the derivative of 2x-1/x ?
The derivative of 2x-1/x is 2+1/(x^2)
What is the first derivative of 2x-1/x ?
The first derivative of 2x-1/x is 2+1/(x^2)