What is laplacetransform f(t)=4t-10 ?

The answer to laplacetransform f(t)=4t-10 is 4/(s^2)-(10)/s

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laplacetransform f(t)=4t-10

laplace transform

f (t) = 4 t - 10

\frac{4}{s ^{2}} - \frac{10}{s}

Solution steps

L {4 t - 10}

Use the linearity property of Laplace Transform:

For functions

f (t), g (t)

and constants

a, b : L {a \cdot f (t) + b \cdot g (t)} = a \cdot L {f (t)} + b \cdot L {g (t)}

= 4 L {t} - L {10}

L {t} : \frac{1}{s ^{2}}

L {10} : \frac{10}{s}

= 4 \cdot \frac{1}{s ^{2}} - \frac{10}{s}

Refine

4 \frac{1}{s ^{2}} - \frac{10}{s} : \frac{4}{s ^{2}} - \frac{10}{s}

= \frac{4}{s ^{2}} - \frac{10}{s}

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What is laplacetransform f(t)=4t-10 ?
The answer to laplacetransform f(t)=4t-10 is 4/(s^2)-(10)/s