What is the derivative of (4x-3^2) ?

The derivative of (4x-3^2) is 8(4x-3)

What is the first derivative of (4x-3^2) ?

The first derivative of (4x-3^2) is 8(4x-3)

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\frac{d}{d x} ((4 x - 3)^{2})

8 (4 x - 3)

Solution steps

\frac{d}{d x} ((4 x - 3)^{2})

Apply the chain rule:

2 (4 x - 3) \frac{d}{d x} (4 x - 3)

= 2 (4 x - 3) \frac{d}{d x} (4 x - 3)

\frac{d}{d x} (4 x - 3) = 4

= 2 (4 x - 3) \cdot 4

Simplify

= 8 (4 x - 3)

x^{(\frac{4}{3})}, 2 x^{(\frac{1}{3})}, 0, 2

(e^{y} + 1)^{2} e^{- y} d x + (e^{x} + 1)^{5} e^{- x} d y = 0

\int \frac{sec ( x )}{sec ( x ) - tan ( x )} d x

x \to 0 - lim (arcsin (e^{x}))

y = 6 x^{2} - 2 x, y = x^{3} - 6 x + 5

What is the derivative of (4x-3^2) ?
The derivative of (4x-3^2) is 8(4x-3)
What is the first derivative of (4x-3^2) ?
The first derivative of (4x-3^2) is 8(4x-3)