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Popular >

y^'+2xy=x,y(0)=3

Solution

y^{^{'}} + 2 x y = x, y (0) = 3

Solution

y = \frac{5 e ^{- x^{2}}}{2} + \frac{1}{2}

Solution steps

y^{'} (x) + 2 x y = x

Solve separable ODE:

y = \frac{5 e ^{- x^{2}}}{2} + \frac{1}{2}

y = \frac{5 e ^{- x^{2}}}{2} + \frac{1}{2}

Graph

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Frequently Asked Questions (FAQ)

What is the solution for y^'+2xy=x,y(0)=3 ?
The solution for y^'+2xy=x,y(0)=3 is y=(5e^{-x^2})/2+1/2