What is the integral of (e^{x^2})/(2x)*5x^4 ?

The integral of (e^{x^2})/(2x)*5x^4 is 5/4 (e^{x^2}x^2-e^{x^2})+C

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integral of (e^{x^2})/(2x)*5x^4

\int \frac{e ^{x^{2}}}{2 x} \cdot 5 x^{4} d x

\frac{5}{4} (e^{x^{2}} x^{2} - e^{x^{2}}) + C

Solution steps

\int \frac{e ^{x^{2}}}{2 x} \cdot 5 x^{4} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{2} \cdot 5 \cdot \int \frac{e ^{x^{2}}}{x} x^{4} d x

\frac{1}{2} \cdot 5 = \frac{5}{2}

= \frac{5}{2} \cdot \int \frac{e ^{x^{2}}}{x} x^{4} d x

Simplify

\frac{e ^{x^{2}}}{x} x^{4} : e^{x^{2}} x^{3}

= \frac{5}{2} \cdot \int e^{x^{2}} x^{3} d x

Apply u-substitution

: \int \frac{e ^{u} u}{2} d u

= \frac{5}{2} \cdot \int \frac{e ^{u} u}{2} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{5}{2} \cdot \frac{1}{2} \cdot \int e^{u} u d u

Apply Integration By Parts

: e^{u} u - \int e^{u} d u

= \frac{5}{2} \cdot \frac{1}{2} (e^{u} u - \int e^{u} d u)

\int e^{u} d u = e^{u}

= \frac{5}{2} \cdot \frac{1}{2} (e^{u} u - e^{u})

Substitute back

u = x^{2}

= \frac{5}{2} \cdot \frac{1}{2} (e^{x^{2}} x^{2} - e^{x^{2}})

Simplify

\frac{5}{2} \cdot \frac{1}{2} (e^{x^{2}} x^{2} - e^{x^{2}}) : \frac{5}{4} (e^{x^{2}} x^{2} - e^{x^{2}})

= \frac{5}{4} (e^{x^{2}} x^{2} - e^{x^{2}})

Add a constant to the solution

= \frac{5}{4} (e^{x^{2}} x^{2} - e^{x^{2}}) + C

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\int \frac{( a + x )}{( a - x )} d x

What is the integral of (e^{x^2})/(2x)*5x^4 ?
The integral of (e^{x^2})/(2x)*5x^4 is 5/4 (e^{x^2}x^2-e^{x^2})+C