What is the first derivative of y=2x-8 ?

The first derivative of y=2x-8 is 2

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derivative of y=2x-8

derivative of

y = 2 x - 8

2

Solution steps

\frac{d}{d x} (2 x - 8)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x) - \frac{d}{d x} (8)

\frac{d}{d x} (2 x) = 2

\frac{d}{d x} (8) = 0

= 2 - 0

Simplify

= 2

x \to 1 lim (\frac{1}{x ( x + 2 )})

(1, - 7), (2, - 1)

m^{2} (\frac{c}{2} - \frac{m}{3})

\int \frac{1}{25 x ^{2} + 16} d x

x \to 2 lim (\frac{x}{x ^{2} - 3 x + 2})