What is (\partial)/(\partial x)(cos(x)sec^2(y)) ?

The answer to (\partial)/(\partial x)(cos(x)sec^2(y)) is -sin(x)sec^2(y)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(\partial)/(\partial x)(cos(x)sec^2(y))

\frac{\partial}{\partial x} (cos (x) sec^{2} (y))

- sin (x) sec^{2} (y)

Solution steps

\frac{\partial}{\partial x} (cos (x) sec^{2} (y))

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= sec^{2} (y) \frac{\partial}{\partial x} (cos (x))

Apply the common derivative:

\frac{\partial}{\partial x} (cos (x)) = - sin (x)

= sec^{2} (y) (- sin (x))

Simplify

= - sin (x) sec^{2} (y)

\frac{\partial}{\partial x} (\frac{e ^{x}}{x + y ^{3}})

\int \frac{4}{sec ( 2 x ) - 1} d x

\int_{0}^{3} \frac{x - 1}{x ^{2} - 3 x - 4} d x

\int \frac{7 x ^{3} + 4 x + 4 x ^{2} + 1}{x ^{4} + x ^{2}} d x

\frac{d}{d x} (\frac{- 2 x}{1 - x ^{2}})

What is (\partial)/(\partial x)(cos(x)sec^2(y)) ?
The answer to (\partial)/(\partial x)(cos(x)sec^2(y)) is -sin(x)sec^2(y)