What is (\partial)/(\partial z)(xy+z) ?

The answer to (\partial)/(\partial z)(xy+z) is 1

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(\partial)/(\partial z)(xy+z)

\frac{\partial}{\partial z} (x y + z)

1

Solution steps

\frac{\partial}{\partial z} (x y + z)

Treat

x, y

as constants

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial z} (x y) + \frac{\partial}{\partial z} (z)

\frac{\partial}{\partial z} (x y) = 0

\frac{\partial}{\partial z} (z) = 1

= 0 + 1

Simplify

= 1

y^{^{'}} = 1 + 4 y^{2}, y (1) = 0

\int_{1}^{2} x^{3} x^{4} + 5 d x

x \to \infty lim (x^{3} - 6 x)

\int 10 arctan (x) d x

\frac{\partial}{\partial x} (ln (x^{7} + y^{5}))

What is (\partial)/(\partial z)(xy+z) ?
The answer to (\partial)/(\partial z)(xy+z) is 1