What is the limit as x approaches 3 of 1/(2^x-8) ?

The limit as x approaches 3 of 1/(2^x-8) is diverges

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limit as x approaches 3 of 1/(2^x-8)

x \to 3 lim (\frac{1}{2 ^{x} - 8})

diverges

Solution steps

x \to 3 lim (\frac{1}{2 ^{x} - 8})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 3 + lim (\frac{1}{2 ^{x} - 8}) = \infty

x \to 3 - lim (\frac{1}{2 ^{x} - 8}) = - \infty

= diverges

x \to 0 lim (\frac{x}{tan ( 5 x )})

\int \frac{sin ( 2 x )}{cos ^{2} ( 2 x )} d x

x \to 1 lim (x + 2)

f (x) = ln (3 x^{2} - 7 x + 4)

\frac{d y}{d x} = \frac{y}{x} + 1

What is the limit as x approaches 3 of 1/(2^x-8) ?
The limit as x approaches 3 of 1/(2^x-8) is diverges