What is the solution for y^'=(9x)/(y+x^2y) ?

The solution for y^'=(9x)/(y+x^2y) is y=sqrt(9ln(1+x^2)+c_{1)},y=-sqrt(9ln(1+x^2)+c_{1)}

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y^'=(9x)/(y+x^2y)

y^{^{'}} = \frac{9 x}{y + x ^{2} y}

y = 9 ln (1 + x^{2}) + c_{1}, y = - 9 ln (1 + x^{2}) + c_{1}

Solution steps

y^{'} (x) = \frac{9 x}{y + x ^{2} y}

Solve separable ODE:

y = 9 ln (1 + x^{2}) + c_{1}, y = - 9 ln (1 + x^{2}) + c_{1}

y = 9 ln (1 + x^{2}) + c_{1}, y = - 9 ln (1 + x^{2}) + c_{1}

\frac{d}{d x} (2 x + \frac{1}{2 x})

\frac{y ^{^{'}}}{2} = y

x \to \frac{π}{2} + lim (e^{s e c (x)})

\int 5 θ sec^{2} (θ) d θ

\int \frac{( 25 - x ^{2} ) ^{3}}{x ^{4}} d x

What is the solution for y^'=(9x)/(y+x^2y) ?
The solution for y^'=(9x)/(y+x^2y) is y=sqrt(9ln(1+x^2)+c_{1)},y=-sqrt(9ln(1+x^2)+c_{1)}