What is the solution for y^{''}+25y=10sin(5x) ?

The solution for y^{''}+25y=10sin(5x) is y=c_{1}cos(5x)+c_{2}sin(5x)-xcos(5x)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^{''}+25y=10sin(5x)

y^{^{''}} + 25 y = 10 sin (5 x)

y = c_{1} cos (5 x) + c_{2} sin (5 x) - x cos (5 x)

Solution steps

y^{''} (x) + 25 y = 10 sin (5 x)

Solve linear ODE:

y = c_{1} cos (5 x) + c_{2} sin (5 x) - x cos (5 x)

y = c_{1} cos (5 x) + c_{2} sin (5 x) - x cos (5 x)

x \to 0 lim (ln (3 - x))

\frac{s}{s ^{2} + 8}

e^{x}, 5

f (x) = \frac{5}{x}, at x = - \frac{1}{5}

\int_{\frac{π}{6}}^{\infty} \frac{2}{x} d x

What is the solution for y^{''}+25y=10sin(5x) ?
The solution for y^{''}+25y=10sin(5x) is y=c_{1}cos(5x)+c_{2}sin(5x)-xcos(5x)