What is the derivative of (8x-1^3(2x+1)^4) ?

The derivative of (8x-1^3(2x+1)^4) is 24(8x-1)^2(2x+1)^4+8(2x+1)^3(8x-1)^3

What is the first derivative of (8x-1^3(2x+1)^4) ?

The first derivative of (8x-1^3(2x+1)^4) is 24(8x-1)^2(2x+1)^4+8(2x+1)^3(8x-1)^3

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\frac{d}{d x} ((8 x - 1)^{3} (2 x + 1)^{4})

24 (8 x - 1)^{2} (2 x + 1)^{4} + 8 (2 x + 1)^{3} (8 x - 1)^{3}

Solution steps

\frac{d}{d x} ((8 x - 1)^{3} (2 x + 1)^{4})

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = (8 x - 1)^{3}, g = (2 x + 1)^{4}

= \frac{d}{d x} ((8 x - 1)^{3}) (2 x + 1)^{4} + \frac{d}{d x} ((2 x + 1)^{4}) (8 x - 1)^{3}

\frac{d}{d x} ((8 x - 1)^{3}) = 24 (8 x - 1)^{2}

\frac{d}{d x} ((2 x + 1)^{4}) = 8 (2 x + 1)^{3}

= 24 (8 x - 1)^{2} (2 x + 1)^{4} + 8 (2 x + 1)^{3} (8 x - 1)^{3}

\int x \cdot cos (a x) d x

\frac{4 x + 3}{x - 1} (2.11)

y = 3 x^{2} - 3 x + 4

\frac{d y}{d x} = 15 + 5 y + 3 x + y x

f^{^{'}} (x) = x^{2}

What is the derivative of (8x-1^3(2x+1)^4) ?
The derivative of (8x-1^3(2x+1)^4) is 24(8x-1)^2(2x+1)^4+8(2x+1)^3(8x-1)^3
What is the first derivative of (8x-1^3(2x+1)^4) ?
The first derivative of (8x-1^3(2x+1)^4) is 24(8x-1)^2(2x+1)^4+8(2x+1)^3(8x-1)^3