What is (\partial)/(\partial x)(y^4sin(2x)) ?

The answer to (\partial)/(\partial x)(y^4sin(2x)) is y^4cos(2x)*2

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(\partial)/(\partial x)(y^4sin(2x))

\frac{\partial}{\partial x} (y^{4} sin (2 x))

y^{4} cos (2 x) \cdot 2

Solution steps

\frac{\partial}{\partial x} (y^{4} sin (2 x))

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= y^{4} \frac{\partial}{\partial x} (sin (2 x))

Apply the chain rule:

cos (2 x) \frac{\partial}{\partial x} (2 x)

= cos (2 x) \frac{\partial}{\partial x} (2 x)

\frac{\partial}{\partial x} (2 x) = 2

= y^{4} cos (2 x) \cdot 2

x \to - 4 lim (\frac{x ^{2} - 9}{4 - x})

f (x) = 6 e^{- \frac{1}{6} x^{2}}

\int 24 y (1 - x - y) d y

\frac{\partial}{\partial x} (y e^{\frac{x}{y}})

\frac{d}{d x} (\frac{( 3 x + 1 )}{x ^{\frac{2}{3}}})

What is (\partial)/(\partial x)(y^4sin(2x)) ?
The answer to (\partial)/(\partial x)(y^4sin(2x)) is y^4cos(2x)*2