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Popular >

2y^'+10y=80,y(0)=0

Solution

2 y^{^{'}} + 10 y = 80, y (0) = 0

Solution

y = - 8 e^{- 5 t} + 8

Solution steps

2 y^{'} (t) + 10 y = 80

Solve separable ODE:

y = - 8 e^{- 5 t} + 8

y = - 8 e^{- 5 t} + 8

Popular Examples

(\partial)/(\partial x)(sqrt(8-2x^2-y^2))

\frac{\partial}{\partial x} (8 - 2 x^{2} - y^{2})

derivative of g(0)=(4-2x)e^n-4 derivative of

g (0) = (4 - 2 x) e^{n} - 4

limit as x approaches-1 of 5-x^2

x \to - 1 lim (5 - x^{2})

derivative of (pix)/4 derivative of

\frac{π x}{4}

y^{^{'}} = 4 x (x - 2)

Frequently Asked Questions (FAQ)

What is the solution for 2y^'+10y=80,y(0)=0 ?
The solution for 2y^'+10y=80,y(0)=0 is y=-8e^{-5t}+8