What is the d/(dθ)(5+5sin(θ)) ?

The d/(dθ)(5+5sin(θ)) is 5cos(θ)

What is the first d/(dθ)(5+5sin(θ)) ?

The first d/(dθ)(5+5sin(θ)) is 5cos(θ)

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\frac{d}{d θ} (5 + 5 sin (θ))

5 cos (θ)

Solution steps

\frac{d}{d θ} (5 + 5 sin (θ))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d θ} (5) + \frac{d}{d θ} (5 sin (θ))

\frac{d}{d θ} (5) = 0

\frac{d}{d θ} (5 sin (θ)) = 5 cos (θ)

= 0 + 5 cos (θ)

Simplify

= 5 cos (θ)

(- 1)^{^{'}}

\frac{\partial}{\partial x} (\frac{x - y}{x + z})

y^{^{'}} = \frac{- 1}{x} y + 2

\frac{d}{d t} (5 sin (t))

2 (sin (2 t)) e^{- 2 t}