What is inverse oflaplace 2/(s^2) ?

The answer to inverse oflaplace 2/(s^2) is 2t

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inverse oflaplace 2/(s^2)

inverse laplace

\frac{2}{s ^{2}}

2 t

Solution steps

L^{- 1} {\frac{2}{s ^{2}}}

= L^{- 1} {2 \cdot \frac{1}{s ^{2}}}

Use the constant multiplication property of Inverse Laplace Transform:

For function

f (t)

and constant

a : L^{- 1} {a \cdot f (t)} = a \cdot L^{- 1} {f (t)}

= 2 L^{- 1} {\frac{1}{s ^{2}}}

Use Inverse Laplace Transform table:

L^{- 1} {\frac{( n ) !}{s ^{n + 1}}} = t^{n}

L^{- 1} {\frac{1}{s ^{2}}} = t

= 2 t

x \to 5 lim (10)

\int sin^{7} (x co) s^{4} x d x

\frac{\partial}{\partial x} (6 y^{9} x^{5} - 5 y^{8} x^{4})

x \to \infty lim (- x R (x) C (x))

y^{^{'}} = \frac{( e ^{(x - y)} )}{1 + e ^{x}}, y (1) = 0

What is inverse oflaplace 2/(s^2) ?
The answer to inverse oflaplace 2/(s^2) is 2t