What is the integral from 1 to 3 of 1/(x^3) ?

The integral from 1 to 3 of 1/(x^3) is 4/9

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integral from 1 to 3 of 1/(x^3)

\int_{1}^{3} \frac{1}{x ^{3}} d x

\frac{4}{9}

Decimal Notation

0.44444 \dots

Solution steps

\int_{1}^{3} \frac{1}{x ^{3}} d x

Apply the Power Rule

: [- \frac{1}{2 x ^{2}}]_{1}^{3}

= [- \frac{1}{2 x ^{2}}]_{1}^{3}

Compute the boundaries:

\frac{4}{9}

= \frac{4}{9}

x 3 - x^{2}

x \to 2 lim (\frac{1}{∣ 2 - x ∣})

y = - x^{2} + 8 x - 12, y = x^{2} - 8 x + 18, x = 3 x = 6

f (x) = 6 x^{2} + 4 x - 7, - 3

\int \frac{( arcsin ( \frac{x}{3} ) ) ^{2}}{9 - x ^{2}} d x

What is the integral from 1 to 3 of 1/(x^3) ?
The integral from 1 to 3 of 1/(x^3) is 4/9