What is the derivative of (x^2+3x+2/(x+1)) ?

The derivative of (x^2+3x+2/(x+1)) is 1

What is the first derivative of (x^2+3x+2/(x+1)) ?

The first derivative of (x^2+3x+2/(x+1)) is 1

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\frac{d}{d x} (\frac{x ^{2} + 3 x + 2}{x + 1})

1

Solution steps

\frac{d}{d x} (\frac{x ^{2} + 3 x + 2}{x + 1})

Simplify

\frac{x ^{2} + 3 x + 2}{x + 1} : x + 2

= \frac{d}{d x} (x + 2)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d x}{d x} + \frac{d}{d x} (2)

\frac{d x}{d x} = 1

\frac{d}{d x} (2) = 0

= 1 + 0

Simplify

= 1

\frac{9}{( s - 2 ) ( s - 3 )}

f (x) = (2 x) (4 x^{2} + 6 x^{7} + 8)

\int \frac{1}{b ^{2} + a ^{2} x ^{2}} d x

\int x^{2} ln (x) + e^{2 x} + 1 d x

\frac{d}{d x} (x^{2} - \frac{1}{x})

What is the derivative of (x^2+3x+2/(x+1)) ?
The derivative of (x^2+3x+2/(x+1)) is 1
What is the first derivative of (x^2+3x+2/(x+1)) ?
The first derivative of (x^2+3x+2/(x+1)) is 1