What is (\partial)/(\partial y)(sin(xyz)) ?

The answer to (\partial)/(\partial y)(sin(xyz)) is cos(xyz)xz

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(\partial)/(\partial y)(sin(xyz))

\frac{\partial}{\partial y} (sin (x yz))

cos (x yz) x z

Solution steps

\frac{\partial}{\partial y} (sin (x yz))

Treat

x, z

as constants

Apply the chain rule:

cos (x yz) \frac{\partial}{\partial y} (x yz)

= cos (x yz) \frac{\partial}{\partial y} (x yz)

\frac{\partial}{\partial y} (x yz) = x z

= cos (x yz) x z

\frac{d}{d x} (\frac{4}{5 x})

\frac{d y}{d x} + 3 x^{2} y = 0

\frac{d}{d y} (\frac{y}{x ^{2} + y ^{2} + 1})

\int_{0}^{1} 2 π x (18 - 18 x) d x

\int sin^{2} (x) cos (x) ln (sin (x)) d x

What is (\partial)/(\partial y)(sin(xyz)) ?
The answer to (\partial)/(\partial y)(sin(xyz)) is cos(xyz)xz