en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^'+ay=0

Solution

y^{^{'}} + a y = 0

Solution

y = e^{- a t + c_{1}}

Solution steps

y^{'} (t) + a y (t) = 0

Solve separable ODE:

y = e^{- a t + c_{1}}

y = e^{- a t + c_{1}}

Popular Examples

derivative of 3x^e

\frac{d}{d x} (3 x^{e})

sum from n=1 to infinity of ((1))/(n!)

n = 1 \sum \infty \frac{( 1 )}{n !}

area 3sqrt(x),3x area

3 x, 3 x

y^{^{'}} - 6 y + 1 = 0

y^{^{''}} + y = t e^{t}

Frequently Asked Questions (FAQ)

What is the solution for y^'+ay=0 ?
The solution for y^'+ay=0 is y=e^{-at+c_{1}}